4p^2-30p-10=0

Solution for 4p^2-30p-10=0 equation:

4p^2-30p-10=0

a = 4; b = -30; c = -10;
Δ = b2-4ac
Δ = -302-4·4·(-10)
Δ = 1060
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1060}=\sqrt{4*265}=\sqrt{4}*\sqrt{265}=2\sqrt{265}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-2\sqrt{265}}{2*4}=\frac{30-2\sqrt{265}}{8}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+2\sqrt{265}}{2*4}=\frac{30+2\sqrt{265}}{8}
$